Spørgsmål # 7bd2c

Spørgsmål # 7bd2c
Anonim

Svar:

Mulighed (A) accepteres her.

Forklaring:

I betragtning af at

# Rarrsintheta + costheta = sqrt (2) cosalpha #

# Rarrcostheta * (1 / sqrt (2)) + sintheta * (1 / sqrt (2)) = cosalpha #

# Rarrcostheta * cos (pi / 4) + sintheta * sin (pi / 4) = cosalpha #

#rarrcos (theta-pi / 4) = cos (2npi + -a) #

# Rarrtheta = 2npi + -alfa + pi / 4 #