Svar:
#COLOR (blå) (x = 4) farve (hvid) ("XX") orcolor (hvid) ("XX") farve (blå) (x = -2) #
Forklaring:
Givet
#COLOR (hvid) ("XXX") 2 / (x + 6) + (2x) / (x + 4) = (3x) / (x + 6) #
#rArr farve (hvid) ("XX") (2x) / (x + 4) = (3x-2) / (x + 6) #
krydsmultiplikation:
#color (hvid) ("XXX") (2x) xx (x + 6) = (3x-2) xx (x + 4) #
#rArrcolor (hvid) ("XX") 2x ^ 2 + 12x = 3x ^ 2 + 10x-8 #
#rArrcolor (hvid) ("XX") x ^ 2-2x-8 = 0 #
#rArrcolor (hvid) ("XX") (x-4) (x + 2) = 0 #
#rArr {:(x-4 = 0, farve (hvid) ("XX") orcolor (hvid) ("XX"), x + 2 = 0), (rarrx = 4, rarrx = -2):} #