Antag at g (x) = 5x ^ 4-15x ^ 2-32. Hvordan løser du ligningen for x, hvis g (x) = - 32? Hvad med g (x) = 58?

Antag at g (x) = 5x ^ 4-15x ^ 2-32. Hvordan løser du ligningen for x, hvis g (x) = - 32? Hvad med g (x) = 58?
Anonim

Svar:

Sag 1: #g (x) = - 32 rarr farve (grøn) (x i {0, + - sqrt (93)}) #

Sag 2: #g (x) = 58 rarr farve (grøn) (x i {+ -sqrt (6), + - sqrt (3) i}) #

Forklaring:

Givet: #COLOR (blå) (g (x) = 5x ^ 4-15x ^ 2-32 #

Del 1: #farve (rød) ("Hvis" g (x) = - 32) #

#COLOR (rød) (- 32) = farve (blå) (5x ^ 4-15x ^ 2-32) #

#rarr farve (blå) (5x ^ 4-15x ^ 2) = 0 #

#rarr 5xxx ^ 2xx (x ^ 2-3) = 0 #

#rarr {(x ^ 2 = 0, farve (hvid) ("X") orcolor (hvid) ("X"), x ^ 2-3 = 0), (rarrx = 0, rarrx = + - sqrt 3)):} #

#x i {-sqrt (3), 0, + sqrt (3)} #

Del 2: #farve (rød) ("Hvis" g (x) = 58) #

#COLOR (rød) (58) = farve (blå) (5x ^ 4-15x ^ 2-32) #

#rarr farve (blå) ("5x ^ 4-15x ^ 2) -90 = 0 #

#rarr 5xx (x ^ 2-6) xx (x ^ 2 + 3) = 0 #

#rarr {((x ^ 2-6) = 0, farve (hvid) ("X") orcolor (hvid) ("X"), x ^ 2 + 3 = 0), (rarrx = + - sqrt),, rarrx = + - sqrt (3) i):} #

#x i {-sqrt (6), + sqrt (6), - sqrt (3) i, + sqrt (3) i} #